MTB > #greg vanderlaan homework 8 stat 108

 

Two-Sample T-Test and CI: lake, bay

 

Two-sample T for lake vs bay

 

       N      Mean     StDev   SE Mean

lake  15     183.5      15.8       4.1

bay   12     161.6      11.9       3.4

 

Difference = mu lake - mu bay

Estimate for difference:  21.88

95% CI for difference: (10.52, 33.25)

T-Test of difference = 0 (vs not =): T-Value = 3.97  P-Value = 0.001  DF = 25

Both use Pooled StDev = 14.2

 

Descriptive Statistics: lake, bay

 

Variable             N       Mean     Median     TrMean      StDev    SE Mean

lake                15     183.47     186.00     184.00      15.83       4.09

bay                 12     161.58     163.50     162.00      11.92       3.44

 

Variable       Minimum    Maximum         Q1         Q3

lake            148.00     212.00     173.00     193.00

bay             138.00     181.00     155.25     168.00

 

 

 

 

 

 

 

 

 

 

 

Greg vanderlaan homework #8

Descriptive Statistics: cardiac

 

Variable             N       Mean     Median     TrMean      StDev    SE Mean

cardiac             29      4.496      4.440      4.486      1.139      0.212

 

Variable       Minimum    Maximum         Q1         Q3

cardiac          2.600      6.680      3.520      5.395

 

One-Sample T: cardiac

 

Variable          N      Mean     StDev   SE Mean         95.0% CI   

cardiac          29     4.496     1.139     0.212  (   4.063,   4.930)

 

Yes, 95% CI value is always greater that 4.0