The 5.0 x 10 -14 kg oil
drop to the right has a charge of -3.2 x 10 -19 C.
The oil drop is suspended in midair. What is the magnitude of
the electric field intensity?
A. 6.53 x 10 -7
C. 1.59 x 105
B. 6.27 x 10 -5
D. 1.53 x 106
F = Eq = mg (Force
from electric field, up; must equal force from gravity, down.)
mg 5.0 x 10 -14
kg x 9.80 m s -2
E = ------ = ----------------------------------------- = 1.53 x 106
N/C
q
3.2 x 10 -19 C
