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25.
What is the tension on the rope between the 10.0 kg and 15.0 kg masses?  (Assume no Friction)

A.     49.0 N

B.     98.0 N

C.    120. N

D.    147 N

       
Set down as positive.   Tension is a pull. 

T1 is tension in rope connecting 10.0 kg and 30.0 kg

T2 is tension in rope connecting 10.0 kg and 15.0 kg

Sum Forces = mass x acceleration

Green Object    mgreen g Sin 30o - T2 = - mgreen a

Purple Object   mpurple g Sin 30o + T2 - T1 = - mpurple a

Red Object      mred g - T1 = mreda

NOW SOLVE THE EQUATIONS SIMULTANEOUSLY

T1 = mredg - mreda                                                               (Red Object solved for T1)

mpurple g Sin 30o + T2 - mred g + mred a = - mpurple a        (T1substituted into Purple Object)

T2 = mred g - mpurple a - mred a - mpurple g Sin 30o            (Previous Equation Solved for T2)

mgreen g Sin 30o - mred g + mpurple a + mred a + mpurple g Sin 30o = - mgreen a  

                                                                                              (T2 substituted into Green Object)

NOW GET ALL a TERMS ON LEFT SIDE AND ALL g TERMS ON THE RIGHT SIDE

mpurple a + mred a + mgreen a = mred g - mpurple g Sin 30o -  mgreen g Sin 30o

FACTOR OUT a

a(mpurple + mred  + mgreen) = mred g - mpurple g Sin 30o -  mgreen g Sin 30o 

     
        (mred g - mpurple g Sin 30o -  mgreen g Sin 30o )
a = ----------------------------------------------------------------
                   (mpurple + mred  + mgreen)

  
       ( 30.0 kg x 9.80 m/s2 - 10.0 kg x 9.80 m/s2 x Sin 30o - 15.0 kg x 9.80 m/s2 x Sin 30o)
a = -------------------------------------------------------------------------------------------------------------- =  3.12 m/s2
                                               (10.0 kg  +  30.0 kg  +  15.0 kg)

  
a = =  3.12 m/s2

 

mgreen g Sin 30o - T2 = - mgreen a  

T2  =  mgreen a  +  mgreen g Sin 30o T2  =  15.0 kg x 3.12 m/2  +  15.0 kg x 9.80 m/s2 Sin 30o

T2 = 120. N