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36. A pitcher in baseball walks 25.0 m West turns and walks 15.0 m South.  How far must he throw a ball he hit his original position?
      
A. 29.2 m C. 36.7 m
B. 33.1 m D. 40.0 m
          
X = ( (15m)2  +  (25m)2 ) 1/2  =  29.2 m

The ball must be thrown 29.2 m.

The Correct Answer is A.