A 7.50 kg bowling
ball sliding 35.0 m/s on a frictionless surface is stopped by a spring
with a force constant of 450. N/m. How far is the spring compressed
before it stops?
A.
0.583 m
KE
= 1/2 mv2 = 1/2 kX2
mv2
7.50 kg x(35.0 m s -1)2
X = (--------) 1/2 = ( ---------------------------------)
1/2 = 4.52 m
k
450. kg s -2
