What is the specific heat of a metal if 45.0 g of metal transferred
from boiling water into 225 g of water at 21.2oC reaches
equilibrium with the water at 24.1oC?
The specific heat of water is 4.18 J/goC.
A.
0.162 J/goC
C.
0.405 J/goC
B.
0.364 J/goC
D.
0.809 J/goC
heat gained
=
water 21.2oC
to water 24.1oC
mwatercwater
2.9oC =
- heat
lost
metal 100oC to metal
24.1oC
- mmetalcmetal
( - 74.9oC )
mwatercwater 2.9oC
225 g x 4.18 J/goC x 2.9oC
cmetal = --------------------------- =
-------------------------------------- = 0.809 J/goC
mmetal 74.9oC
45.0 g x 74.9oC
