Combine all the resistors in series in the branch
R₃  +  R₄ = 3.00 ohms + 1.00 ohms = 4.00 ohms

Combine this with the parallel resistor
( (2.00 ohms)^-1 +  (4.00 ohms)^-1 )^-1  =  1.33 ohms

Combine all the resistors in series
1.33 ohms  +  2.00 ohms  +  1.00 ohms  =  4.33 ohms  =  R_T 

V = IR  =  2.00 amps x 4.33 ohms = 8.66 volts

The Correct Answer is C.