1- Equilibrium constant (Keq) for the ionization of water
1 x 10^-14
[H+] [OH-] / [H2O]   
[H+] [OH-
[H+] [A-] / [HA]  

2-  pH =
log[0H-]
-log[H2O]
log[H+]
-log[H+]

3- Dissociation constant (Ka) of a weak acid
[H+] [A-] / [HA]
[HA] / [H+] [A-]
[HA+] / [H+] [A]
[H+] [A] / [HA+]

4- Henderson-Hasselbach equation
pKa + log [HA]/[A-]
pKa + log [A-][H]/[HA]
pKa + log [A-]/[HA]
pKa + log [A-]/[HA][H]

5- Biological buffers
are weak acid ionized less than 50%
maintain pH of biological sistems above 7.0
have a pKa near 7.0
titration with a strong acid yield a curve with the pKa as midpoint

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Answers:

1- Equilibrium constant (Keq) for the ionization of water
Answer: [H+] [OH-] / [H2O]   

2-  pH =
Answer: -log[H+]

3- Dissociation constant (Ka) of a weak acid
Answer: [H+] [A-] / [HA]

4- Henderson-Hasselbach equation
Answer: pKa + log [A-]/[HA]

5- Biological buffers
Answer: have a pKa near 7.0